The paramagnetic property of the oxygen molecule is due to the presence of unpiared electrons present in . So these are diamagnetic. ... NEET 2020 Chemical Bonding and Molecular Structure. Correct option (a) O-2. The correct explanation comes from Molecular Orbital theory. The lowest excited state of the diatomic oxygen molecule is a singlet state.It is a gas with physical properties differing only subtly from those of the more prevalent triplet ground state of O 2.In terms of its chemical reactivity, however, singlet oxygen is far more reactive toward organic compounds. It shows that all the electrons in oxygen are paired, so oxygen should be diamagnetic. In contrast, molecular nitrogen, \(N_2\), has no unpaired electrons and is diamagnetic; it is therefore unaffected by the magnet. NO 2 is paramagnetic due to the presence of unpaired electron on the nitrogen atom. As shown in the video, molecular oxygen (\(O_2\) is paramagnetic and is attracted to is paramagnetic and is attracted to the magnet. 8. NEET 2020 Chemical Bonding and Molecular Structure 8. O-2 is paramagnetic due to the presence of one unpaired electron. The common allotrope of elemental oxygen on Earth, O 2, is generally known as oxygen, but may be called dioxygen, diatomic oxygen, molecular oxygen, or oxygen gas to distinguish it from the element itself and from the triatomic allotrope ozone, O 3.As a major component (about 21% by volume) of Earth's atmosphere, elemental oxygen is most commonly encountered in the diatomic form. Paramagnetism is due to the presence of unpaired electrons in the material, so most atoms with incompletely filled atomic orbitals are paramagnetic, although exceptions such as copper exist. The atomic orbitals of the "O" atoms overlap to form the σ and π orbitals of the "O"_2 molecule … Firstly, let us define the properties of the oxygen we'll be talking about. No it is not paramagnetic.O2^2- has 2 electrons more than O2.Pi 2p molecular orbitals get completely filled hence it is diamagnetic. We now turn to a molecular orbital description of the bonding in \(\ce{O2}\). "O"_2 is paramagnetic because it has two unpaired electrons. Therefore, oxygen has two unpaired electrons and is paramagnetic. Due to their spin, unpaired electrons have a magnetic dipole moment and act like tiny magnets. For something to be magnetic (we say 'paramagnetic'), it must have an inequality in the total electron spin. Explanation: CN-, CO and NO + are isoelectronic with 14 electrons each and there is no unpaired electrons in the MO configuration of these species. > The Lewis structure of "O"_2 gives a misleading impression. The atomic orbitals of the O atoms overlap to form the σ and π orbitals of the O2 molecule as per the molecular orbital theory. The quantum number m s represents the magnetic spin of an electron. B2 = 5 + 5 = 10e-= σ1s2 σ1s2 , σ2s2 σ2s2 , π2px1 π2py1Due to the presence of unpaired electrons, in π bonding orbitals, B2 shows paramagnetic behaviour. If the supply of oxygen is limited, $ {{H}_{2}}S $ reacts with $ {{O}_{2}} $ to form. On electrolysis of dil.sulphuric acid using Platinum (Pt) electrode, the product obtained at anode will be: Yet oxygen is paramagnetic. Molecular Oxygen is Paramagnetic. O 2 has, in total, 12 valence electrons (each oxygen donating six). It so happens that the molecular orbital description of this molecule provided an explanation for a long-standing puzzle that could not be explained using other bonding models. The paramagnetic nature of O 2 is due to unpaired electrons. 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